tag:blogger.com,1999:blog-5730391.post105132437528681029..comments2019-08-20T13:07:49.256-07:00Comments on Blaine's Puzzle Blog: Can you turn 2008 into 73?Blainehttp://www.blogger.com/profile/06379274325110866036noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-5730391.post-50745979393591526092008-04-18T10:28:00.000-07:002008-04-18T10:28:00.000-07:00The solution I had in mind was:sqrt((8 - 0!)! + 0!...The solution I had in mind was:<BR/>sqrt((8 - 0!)! + 0!) + 2Blainehttps://www.blogger.com/profile/06379274325110866036noreply@blogger.comtag:blogger.com,1999:blog-5730391.post-48899870241077997482008-04-15T22:04:00.000-07:002008-04-15T22:04:00.000-07:00Well, I would say that .(0!) to get .1 is breaking...Well, I would say that .(0!) to get .1 is breaking the rules.Blainehttps://www.blogger.com/profile/06379274325110866036noreply@blogger.comtag:blogger.com,1999:blog-5730391.post-92161804661175166022008-04-15T11:37:00.000-07:002008-04-15T11:37:00.000-07:00If I use a factorial to get to 720, multiply by .1...If I use a factorial to get to 720, multiply by .1 and add 1, I get there also without running afoul of digits. Agreed??donhttps://www.blogger.com/profile/10629317119387671011noreply@blogger.comtag:blogger.com,1999:blog-5730391.post-49600798114493886442008-04-14T00:33:00.000-07:002008-04-14T00:33:00.000-07:00From your description, I'd say you've done it.From your description, I'd say you've done it.Blainehttps://www.blogger.com/profile/06379274325110866036noreply@blogger.comtag:blogger.com,1999:blog-5730391.post-18475534563186938622008-04-13T23:20:00.000-07:002008-04-13T23:20:00.000-07:00Got it. I used both the factorial and square root...Got it. I used both the factorial and square root function.EricMargelhttps://www.blogger.com/profile/02090556952649043090noreply@blogger.com