All this historical information was a way to introduce this week's math puzzle.
Q: Using each of the digits in 2008 and standard math operations, can you write an expression that equals 97?Rules:
- Each of the digits 2, 0, 0, 8 must be used. (2 and 8 will appear once, 0 will appear twice.)
- You may use standard math operations of +, -, x, /, √(square root), ^(raise to a power) and !(factorial) along with parentheses for grouping.
- Decimal points and multi-digit numbers may be used (e.g. 20, 208, .02 or 2.8
- If squaring is done, that uses up the digit 2.
- 0! is agreed to have a value of 1.
- Anything raised to the zero power (i.e. x^0) is 1, but 0^0 may not be used (undefined)
- The integer/floor/ceiling/round functions may NOT be used.
- Change of bases may NOT be used.
- Logarithms may NOT be used.
- Sine and Cosine may NOT be used.
I can figure it out several ways with an extra 2, but not using just the digits available:
ReplyDelete((8-0!)^2)*2-0!=97
or
(0!+2)!*8*2-0!=97
You've got the idea but just aren't there yet. It is possible with exactly 4 digits, using the rules given. (P.S. There's a slight typo in your second equation.)
ReplyDeleteIs there any specific strategy, without just guess and check?
ReplyDeleteMy stategy was to work backwards... you figure that you are 1 away from 96, that's a good number since it has lots of factors. So 0! + something...
ReplyDeleteI then realized that 96 was 80% of 120. Hmm... and 120 is 5!, can I use that?
Answer:
(0! / .2)! * .8 + 0!
Great solution. I started with the same premise - 96 was a good starting point. The connection between the factorial and percent eluded me. Thanks for an entertaining puzzle!
ReplyDeleteSeems so easy in hindsight!
ReplyDelete