A Puzzle for Leap Day, 2008 -- Can you make 97?

Today is February 29, a special date that only appears on our calendars every four years. There are exceptions to this 4 year rule on century years (those ending in 00). These years are NOT leap years unless the century is evenly divisible by 400. For example, 2000 was a leap year, but 2100 will NOT be. The cycle of leap years on our calendar repeats in a 400 year cycle. Within that cycle there will be 97 leap years.

All this historical information was a way to introduce this week's math puzzle.

Q: Using each of the digits in 2008 and standard math operations, can you write an expression that equals 97?

Rules:

• Each of the digits 2, 0, 0, 8 must be used. (2 and 8 will appear once, 0 will appear twice.)


• You may use standard math operations of +, -, x, /, √(square root), ^(raise to a power) and !(factorial) along with parentheses for grouping.


• Decimal points and multi-digit numbers may be used (e.g. 20, 208, .02 or 2.8


• If squaring is done, that uses up the digit 2.


• 0! is agreed to have a value of 1.


• Anything raised to the zero power (i.e. x^0) is 1, but 0^0 may not be used (undefined)


• The integer/floor/ceiling/round functions may NOT be used.


• Change of bases may NOT be used.


• Logarithms may NOT be used.


• Sine and Cosine may NOT be used.

Edit: The answer is now available in the comments... but don't look if you still want to figure it out on your own.